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Current Question (ID: 20899)

Question:

$\text{Total number of orbitals that is/are considered as axial orbital(s) is:}$ $p_x, p_y, p_z, d_{xy}, d_{yz}, d_{zx}, d_{x^2-y^2}, d_{z^2}$

Options:

1. $8$
2. $3$
3. $2$
4. $5$

Solution:

$\text{Hint: All the p orbitals are axial orbitals.}$ $\text{Explanation:}$ $(i) \text{p-orbitals are dumbbell shaped with their lobes lying along the axis.}$ $(ii) \text{The general shape of the d-orbitals can be described as "daisy-like" or "four leaf clover" with the exception of the } d_{z^2} \text{ orbital which looks like the donut with a lobe above and below.}$ $\text{The set of orbitals whose lobes line along the axes are called axial orbitals.}$ $\text{So, } p_x, p_y, p_z, d_{x^2-y^2} \text{ and } d_{z^2} \text{ orbitals are called axial orbitals.}$ $\text{Thus, the correct answer is option 4.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}