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Current Question (ID: 20902)

Question:

$\text{Consider the following combination of } n, l, \text{ and } m \text{ values.}$ $\text{(i) } n=3; \ l=0; \ m=0$ $\text{(ii) } n=4; \ l=0; \ m=0$ $\text{(iii) } n=3; \ l=1; \ m=0$ $\text{(iv) } n=3; \ l=2; \ m=0$ $\text{The correct order of energy of the corresponding orbitals for multielectron species:}$

Options:

1. $(ii) > (i) > (iv) > (iii)$
2. $(iv) > (ii) > (iii) > (i)$
3. $(i) > (iii) > (iv) > (ii)$
4. $(iv) > (iii) > (i) > (ii)$

Solution:

$\text{In case of multielectron species energy of electron corresponding to an orbital is } \alpha (n + l).$ $\text{If the value of } n + l \text{ comes out to be same then the one having higher value if } n \text{ has more energy.}$ $\text{(i) } n=3; \ l=0; \ m=0$ $\text{Here, } n + l = 3 + 0 = 3$ $\text{(ii) } n=4; \ l=0; \ m=0$ $\text{Here, } n + l = 4 + 0 = 4$ $\text{(iii) } n=3; \ l=1; \ m=0$ $\text{Here, } n + l = 3 + 1 = 4$ $\text{(iv) } n=3; \ l=2; \ m=0$ $\text{Here, } n + l = 3 + 2 = 5$ $\text{From above we can say that (iv) has maximum energy and (i) has minimum energy.}$ $\text{Among (ii) and (iii) since the value of } (n + l) \text{ is same and (ii) has higher value of } n \text{ therefore (ii) has more energy than (iii).}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}