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Current Question (ID: 20903)

Question:
$\text{Two metals are given:}$ $\text{Metal – 1: Work function} = 4.8 \text{ eV}$ $\text{Metal – 2: Work function} = 2.8 \text{ eV}$ $\text{Photons of wavelength } 350 \text{ nm are incident on both metals separately. Which metal will eject electrons at this wavelength?}$
Options:
  • 1. $\text{Metal-1 only}$
  • 2. $\text{Metal-2 only}$
  • 3. $\text{Both metal-1 and metal-2}$
  • 4. $\text{None of metal-1 and metal-2}$
Solution:
$E_{\text{photon}} = \frac{12400}{3500} = 3.54 \text{ eV}$ $W_{\text{metal-1}} > E_{\text{photon}} > W_{\text{metal-2}}$ $\text{Now, we compare the energy of the photons (3.55 eV) with the work functions:}$ $\text{For Metal – 1: } 3.55 \text{ eV} < 4.8 \text{ eV (no electrons ejected)}$ $\text{For Metal – 2: } 3.55 \text{ eV} > 2.8 \text{ eV (electrons will be ejected)}$ $\text{Only metal 2 will emit photons}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}