Import Question JSON

Current Question (ID: 20914)

Question:

$\text{The correct order of electron gain enthalpy is:}$

Options:

1. $\text{S > Se > Te > O}$
2. $\text{Te > Se > S > O}$
3. $\text{O > S > Se > Te}$
4. $\text{S > O > Se > Te}$

Solution:

$\text{Electron gain enthalpy is the energy associated when one mole of the electron is added to one mole of an element in its isolated gaseous state (ground state).}$ $\text{Left to right across the period electron gain enthalpy increases as the } Z_{\text{eff}} \text{ increases.}$ $\text{Down the group electron gain enthalpy decreases.}$ $\text{The correct order of electron gain enthalpy is:}$ $\text{S > Se > Te > O}$ $\text{The electron gain enthalpy of O is less negative than that of the succeeding element.}$ $\text{This is because when an electron is added to O, the added electron goes to the smaller } n = 2 \text{ quantum level and suffers significant repulsion from the other electrons present in this level.}$ $\text{For the } n = 3 \text{ quantum level (S), the added electron occupies a larger region of space and the electron-electron repulsion is much less.}$ $\text{The values are as follows:}$ $\text{O = -141 kJmol}^{-1}$ $\text{S = -200 kJmol}^{-1}$ $\text{Se = -195 kJmol}^{-1}$ $\text{Te = -190 kJmol}^{-1}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}