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Current Question (ID: 20915)

Question:

$\text{Consider the following compounds:}$ $\text{BeO, BaO, Be(OH)}_2, \text{Sr(OH)}_2$ $\text{The amphoteric compound(s) are:}$

Options:

1. $\text{BeO, BaO}$
2. $\text{BaO, Be(OH)}_2$
3. $\text{Be(OH)}_2, \text{BeO}$
4. $\text{Sr(OH)}_2, \text{Be(OH)}_2$

Solution:

$\text{Hint: Beryllium oxide and hydroxide are amphoteric in nature}$ $\text{Step 1:}$ $\text{Amphoteric oxides behave as acidic with bases and as basic with acids, whereas neutral oxides have no acidic or basic properties.}$ $\text{Basic oxide reacts with acid only and acidic oxide reacts with base only.}$ $\text{Be is thus weak electropositive in nature. Its oxide is amphoteric in nature and reacts with both acid and base.}$ $\text{BeO + H}_2\text{SO}_4 \rightarrow \text{BeSO}_4 + \text{H}_2\text{O}$ $\text{BeO + 2NaOH} \rightarrow \text{Na}_2\text{BeO}_2 + \text{H}_2\text{O}$ $\text{The hydroxide of Be is also amphoteric in nature. The reaction with base and acid is given below:}$ $\text{Be(OH)}_2 + 2\text{HCl} \rightarrow \text{BeCl}_2 + 2\text{H}_2\text{O}$ $\text{Be(OH)}_2 + 2\text{NaOH} \rightarrow \text{Na}_2\text{BeO}_2 + 2\text{H}_2\text{O}$ $\text{BaO and Sr(OH)}_2 \text{ are basic in nature.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}