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Current Question (ID: 20919)

Question:

$\text{The element having a greatest difference between its first and second ionization energies, is:}$

Options:

1. $\text{Ca}$
2. $\text{Sc}$
3. $\text{K}$
4. $\text{Ba}$

Solution:

$\text{Hint: First group element obtained stable noble gas configuration after losing one electron}$ $\text{The first group element has greatest difference between its first and second ionization energies because after losing one electron first group element acquire a noble gas configuration.}$ $\text{For example, potassium atomic number is 19. The electronic configuration of potassium is } 1s^2 \ 2s^2 \ 2p^6 \ 3s^2 \ 3p^6 \ 4s^1. \text{ After losing one electron the electronic configuration is } 1s^2 \ 2s^2 \ 2p^6 \ 3s^2 \ 3p^6 \text{ and it is a stable noble gas configuration. So, removal of second electron is difficult.}$ $\text{Hence, potassium is the correct answer.}$ $\text{The values are as follows:}$ $\text{For potassium, } IE_1 = 418.8 \text{ , and } IE_2 = 3052 \text{ eV}$ $\text{for Ca = 590, 1145 eV}$ $\text{Sc = 633, 1235 eV}$ $\text{Ba = 502, 965 eV}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}