Import Question JSON

Current Question (ID: 20930)

Question:

$\text{Consider the elements Mg, Al, S, P, and Si, the correct increasing order of their first ionization enthalpy is:}$

Options:

1. $\text{Mg} < \text{Al} < \text{Si} < \text{S} < \text{P}$
2. $\text{Al} < \text{Mg} < \text{Si} < \text{S} < \text{P}$
3. $\text{Mg} < \text{Al} < \text{Si} < \text{P} < \text{S}$
4. $\text{Al} < \text{Mg} < \text{S} < \text{Si} < \text{P}$

Solution:

$\text{Hint: Half-filled and fully-filled subshell has high ionization enthalpy}$ $\text{In general from left to right in a period, ionisation enthalpy increases due to effective nuclear charge increases, but due to extra stability of half-filled and fully filled electronic configuration, the ionization enthalpy is more.}$ $\text{The ionization enthalpy of elements i.e. first ionisation enthalpy order is Al} < \text{Mg} < \text{Si} < \text{S} < \text{P}$ $\text{The ionization energy of phosphorus is high than sulphur because P has a half-filled 3p orbital which is more stable than the partially filled 3p orbital of sulphur.}$ $\text{In the same case for Mg and Al, the fully filled 3s orbital of Mg is more stable than the partially filled 3p orbital of Al. Hence, Mg has high ionization energy than Al.}$ $\text{The correct answer is option Al} < \text{Mg} < \text{Si} < \text{S} < \text{P}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}