Import Question JSON

Current Question (ID: 20937)

Question:

$\text{Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R).}$ $\text{Assertion (A):}$ \text{As one moves from left to right in a period, the metallic character decreases while the non-metallic character increases.} $\text{Reason (R):}$ \text{This trend occurs because ionization enthalpy increases and electron gain enthalpy decreases when moving from left to right in a period.} $\text{In light of the above statements, choose the most appropriate answer from the options given below:}$

Options:

1. $\text{Both (A) and (R) are True and (R) is the correct explanation of (A).}$
2. $\text{(A) is False but (R) is True.}$
3. $\text{(A) is True but (R) is False.}$
4. $\text{Both (A) and (R) are True and (R) is not the correct explanation of (A).}$

Solution:

$\text{Explanation:}$ $\text{It is due to increase in both IE \& EA.}$ $\text{Ionization enthalpy does increase (e.g., Na: 496 kJ/mol, Cl: 1251 kJ/mol), making electron loss harder, which supports decreasing metallic character.}$ $\text{However, electron gain enthalpy becomes more negative (e.g., Na: +53 kJ/mol, Cl: -349 kJ/mol), meaning it increases in magnitude, not decreases.}$ $\text{The phrase “decrease in electron gain enthalpy” implies less negative values, which is incorrect for the trend (it becomes more favorable).}$ $\text{The trend in A is driven by nuclear charge and ionization enthalpy, not a decrease in electron gain enthalpy.}$ $\text{Thus, Assertion (A) is correct, but Reason (R) is incorrect due to the error in electron gain enthalpy. So, option 3 is the correct answer.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}