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Current Question (ID: 20939)

Question:

$\text{The increasing order of the atomic radii of the following elements is:}$ $\begin{array}{ccc} (a) & \text{C} & (b) & \text{O} \\ (c) & \text{F} & (d) & \text{Cl} \\ (e) & \text{Br} \end{array}$

Options:

1. $(d) < (c) < (b) < (a) < (e)$
2. $(a) < (b) < (c) < (d) < (e)$
3. $(b) < (c) < (d) < (a) < (e)$
4. $(c) < (b) < (a) < (d) < (e)$

Solution:

$\text{Hint: Down the group, atomic size increases.}$ $\text{As you move from left to right across a period, the number of protons (and therefore the positive charge of the nucleus) increases while the number of electron shells remains the same. This stronger positive charge pulls the electrons closer to the nucleus, decreasing the atomic radius.}$ $\text{As you move down a group, the number of electron shells increases. This means the outermost electrons are further from the nucleus, resulting in a larger atomic radius.}$ $\text{The atomic radii of the given elements are as follows:}$ $\text{F (Fluorine): } \sim 42 \text{ pm}$ $\text{O (Oxygen): } \sim 48 \text{ pm}$ $\text{C (Carbon): } \sim 67 \text{ pm}$ $\text{Cl (Chlorine): } \sim 80 \text{ pm}$ $\text{Br (Bromine): } \sim 90 \text{ pm}$ $\text{The correct order of atomic radius is: F < O < C < Cl < Br}$ $\text{So, option 4 is the correct answer.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}