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Current Question (ID: 20940)

Question:

$\text{The increasing order of the atomic radii of the following elements is:}$ $\begin{array}{ccc} (a) & \text{C} & (b) & \text{O} \\ (c) & \text{F} & (d) & \text{Cl} \\ (e) & \text{Br} \end{array}$

Options:

1. $(d) < (c) < (b) < (a) < (e)$
2. $(a) < (b) < (c) < (d) < (e)$
3. $(b) < (c) < (d) < (a) < (e)$
4. $(c) < (b) < (a) < (d) < (e)$

Solution:

$\text{As you move from left to right across a period, the number of protons (and therefore the positive charge of the nucleus) increases while the number of electron shells remains the same.}$ $\text{This stronger positive charge pulls the electrons closer to the nucleus, decreasing the atomic radius.}$ $\text{As you move down a group, the number of electron shells increases.}$ $\text{This means the outermost electrons are further from the nucleus, resulting in a larger atomic radius.}$ $\text{The atomic radii of the given elements are as follows:}$ $\bullet \ \text{F (Fluorine): } \sim 42 \text{ pm}$ $\bullet \ \text{O (Oxygen): } \sim 48 \text{ pm}$ $\bullet \ \text{C (Carbon): } \sim 67 \text{ pm}$ $\bullet \ \text{Cl (Chlorine): } \sim 80 \text{ pm}$ $\bullet \ \text{Br (Bromine): } \sim 90 \text{ pm}$ $\text{The correct order of atomic radius is: F < O < C < Cl < Br}$ $\text{So, option 4 is the correct answer.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}