Import Question JSON

Current Question (ID: 20958)

Question:

$\text{The structure of PCl}_5 \text{ in the solid state is:}$ $1. \text{ Square pyramidal.}$ $2. \text{ Tetrahedral } [\text{PCl}_4]^+ \text{ and octahedral } [\text{PCl}_6]^- $ $3. \text{ Square planar } [\text{PCl}_4] \text{ and octahedral } [\text{PCl}_6]^- $ $4. \text{ Trigonal bipyramidal.}$

Options:

1. $\text{Square pyramidal.}$
2. $\text{Tetrahedral } [\text{PCl}_4]^+ \text{ and octahedral } [\text{PCl}_6]^-$
3. $\text{Square planar } [\text{PCl}_4] \text{ and octahedral } [\text{PCl}_6]^-$
4. $\text{Trigonal bipyramidal.}$

Solution:

$\text{Hint: In the solid state, PCl}_5 \text{ forms tetrahedral and octahedral complex.}$ $\text{Explanation:}$ $\text{In the solid state, PCl}_5 \text{ prefers to exist as oppositely charged ion like } [\text{PCl}_4]^+ \text{ and } [\text{PCl}_6]^- \text{ as ionic bonding enhances the crystalline nature.}$ $\text{Thus, PCl}_5(\text{s}) \text{ exist as } [\text{PCl}_4]^+ \text{ and } [\text{PCl}_6]^-. \text{ } [\text{PCl}_4]^+ \text{ is sp}^3 \text{ hybridized and it is tetrahedral in shape but } [\text{PCl}_6]^- \text{ is sp}^3d^2 \text{ hybridized and it is octahedral in shape.}$ $\text{So, option 2 is the correct answer.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}