Import Question JSON

Current Question (ID: 20960)

Question:

$\text{The ion that has } sp^3d^2 \text{ hybridization for the central atom is:}$

Options:

1. $[\text{ICl}_4]^{-}$
2. $[\text{ICl}_2]^{-}$
3. $[\text{BrF}_2]^{-}$
4. $[\text{IF}_6]^{-}$

Solution:

$\text{Hint: Use steric number formula, that is, Steric number = } \frac{1}{2} \times (V + M - C + A)$ $\text{Use the formula of steric number. The formula is as follows:}$ $\text{Steric number} = \frac{1}{2} \times (V + M - C + A)$ $\text{Here, } V \text{ is valence electron of central atom, } M \text{ is monovalent atom, } C \text{ is positive charge on compound and } A \text{ is negative charge on compound.}$ $\begin{array}{|c|c|c|} \hline \text{Species} & \text{Calculate steric number} & \text{Hybrid} \\ \hline [\text{ICl}_4]^{-} & \text{Steric number} = \frac{1}{2} \times (7 + 4 + 1) = 6 & sp^3d^2 \\ \hline [\text{ICl}_2]^{-} & \text{Steric number} = \frac{1}{2} \times (7 + 2 + 1) = 5 & sp^3d \\ \hline [\text{BrF}_2]^{-} & \text{Steric number} = \frac{1}{2} \times (7 + 2 + 1) = 5 & sp^3d \\ \hline [\text{IF}_6]^{-} & \text{Steric number} = \frac{1}{2} \times (7 + 6 + 1) = 7 & sp^3d^3 \\ \hline \end{array}$ $\text{Hence, option 1 is the correct answer.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}