Import Question JSON

Current Question (ID: 20963)

Question:
$\text{Among the following, the molecule expected to be stabilized by anion formation is: } \text{C}_2, \text{O}_2, \text{NO}, \text{F}_2$
Options:
  • 1. $\text{NO}$
  • 2. $\text{O}_2$
  • 3. $\text{C}_2$
  • 4. $\text{F}_2$
Solution:
$\text{Bond order is directly proportional to the stability of the species.}$ $\text{The stability depends on the bond order of the molecule. If bond order increases in the anion form, hence stability increases or vice versa.}$ $\text{As per the MOT diagram, the bond order of a given compound and its anion is as follows:}$ $(i) \text{F}_2 \text{ bond order is } 1 \text{ and } \text{F}_2^- \text{ bond order is } 0.5.$ $(ii) \text{NO bond order is } 2.5 \text{ and } \text{NO}^- \text{ bond order is } 2.0.$ $(iii) \text{C}_2 \text{ bond order is } 2 \text{ and } \text{C}_2^- \text{ is } 2.5.$ $\text{Here, the bond order increases, thus, } \text{C}_2^- \text{ is more stable than } \text{C}_2.$ $(iv) \text{O}_2 \text{ bond order is } 2, \text{ and } \text{O}_2^- \text{ is } 1.5.$ $\text{Hence, option 3 is the correct answer.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}