Import Question JSON

Current Question (ID: 20972)

Question:

$\text{Lattice energy for an ionic compound relies on:}$

Options:

1. $\text{The size and charge of the ion.}$
2. $\text{Packing of ions only}$
3. $\text{Size of the ions only}$
4. $\text{Charge on the ions only}$

Solution:

$\text{Hint: Lattice energy depends on the size of ion and charge on ion}$ $\text{The lattice energy (U) of a crystal is the energy evolved when one gram molecule (1 mole) of the crystal is formed from gaseous ions.}$ $\text{The lattice energies cannot be measured directly, but experimental values are obtained from thermodynamic data using the Born–Haber cycle.}$ $\text{The lattice energy of an ionic compound depends upon several factors. These factors are as follows:}$ $1. \text{The lattice becomes stronger (i.e. the lattice energy U becomes more negative), as r the inter-ionic distance decreases. U is proportional to } \frac{1}{r}. \text{ Hence, lattice energy depends on the size of the ion.}$ $2. \text{The lattice energy depends on the product of the ionic charges, and U is proportional to } (z^+ z^-). \text{ Hence, lattice energy depends on the charge on the ion.}$ $\text{Hence, option 1 is the correct answer.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}