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Current Question (ID: 20976)

Question:
$\text{In the anion HCOO}^- \text{ the two carbon-oxygen bonds are found to be of equal length. What is the reason for it?}$
Options:
  • 1. $\text{Electronic orbits of the carbon atom are hybridized}$
  • 2. $\text{The C = O bond is weaker than the C - O bond}$
  • 3. $\text{The anion HCOO}^- \text{ has two resonating structures}$
  • 4. $\text{The anion is obtained by removal of a proton from the acid molecule}$
Solution:
$\text{Hint: In HCOO}^-, \text{ resonance takes place.}$ $\text{In HCOO}^-, \text{ resonance takes place. Resonance is a way of describing bonding in certain molecules or polyatomic ions by the combination of several contributing structures (or forms, also variously known as resonance structures or canonical structures) into a resonance hybrid.}$ $\text{The resonance structures of HCOO}^- \text{ are as follows:}$ $\text{Because of resonance, the anion has two resonating structures and both CO bonds get partially double bond character hence, both bond lengths are equal.}$ $\text{Thus, option third is the correct answer.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}