Import Question JSON

$\text{Hint: Bond strength is directly proportional to the bond order.}$ $\text{Step 1: The bond order is calculated as follows:}$ $\frac{\text{Number of bonding electrons} - \text{Number of antibonding electrons}}{2}$ $\text{The bond order for the given molecules is calculated as follows:}$ $\begin{array}{|c|c|c|} \hline \text{S.No.} & \text{Molecule} & \text{Electronic configuration} \\ \hline 1 & \text{B}_2 & (\sigma_{1s})^2 (\sigma^*_{1s})^2 (\sigma_{2s})^2 (\sigma^*_{2s})^2 (\pi_{2p_x})^1 (\pi_{2p_y})^1 \\ 2 & \text{B}_2^+ & (\sigma_{1s})^2 (\sigma^*_{1s})^2 (\sigma_{2s})^2 (\sigma^*_{2s})^2 (\pi_{2p_x})^1 (\pi_{2p_y})^0 \\ 3 & \text{NO} & (\sigma_{1s})^2 (\sigma^*_{1s})^2 (\sigma_{2s})^2 (\sigma^*_{2s})^2 (\pi_{2p_x})^2 (\pi_{2p_y})^1 \\ 4 & \text{NO}^+ & (\sigma_{1s})^2 (\sigma^*_{1s})^2 (\sigma_{2s})^2 (\sigma^*_{2s})^2 (\pi_{2p_x})^2 (\pi_{2p_y})^2 \\ 5 & \text{N}_2 & (\sigma_{1s})^2 (\sigma^*_{1s})^2 (\sigma_{2s})^2 (\sigma^*_{2s})^2 (\pi_{2p_x})^2 (\pi_{2p_y})^2 \\ 6 & \text{N}_2^+ & (\sigma_{1s})^2 (\sigma^*_{1s})^2 (\sigma_{2s})^2 (\sigma^*_{2s})^2 (\pi_{2p_x})^2 (\pi_{2p_y})^1 \\ 7 & \text{O}_2 & (\sigma_{1s})^2 (\sigma^*_{1s})^2 (\sigma_{2s})^2 (\sigma^*_{2s})^2 (\pi_{2p_x})^2 (\pi_{2p_y})^2 (\pi^*_{2p_x})^1 (\pi^*_{2p_y})^1 \\ 8 & \text{O}_2^+ & (\sigma_{1s})^2 (\sigma^*_{1s})^2 (\sigma_{2s})^2 (\sigma^*_{2s})^2 (\pi_{2p_x})^2 (\pi_{2p_y})^2 (\pi^*_{2p_x})^2 (\pi^*_{2p_y})^1 \\ 9 & \text{C}_2 & (\sigma_{1s})^2 (\sigma^*_{1s})^2 (\sigma_{2s})^2 (\sigma^*_{2s})^2 (\pi_{2p_x})^2 (\pi_{2p_y})^2 \\ 10 & \text{C}_2^+ & (\sigma_{1s})^2 (\sigma^*_{1s})^2 (\sigma_{2s})^2 (\sigma^*_{2s})^2 (\pi_{2p_x})^2 (\pi_{2p_y})^1 \\ \hline \end{array}$ $\text{Step 2: Removing an electron from an antibonding molecular orbital increases the bond order of a molecule. This is because the antibonding orbital destabilizes the molecule by increasing its energy.}$ $\text{Among the given molecules, the bond order increases when an electron is removed from } \text{NO} \text{ and } \text{O}_2. \text{ So, the bond strength of } \text{NO} \text{ and } \text{O}_2 \text{ increases when an electron is removed from these species.}$ $\text{Hence, option 1 is the correct answer.}$