Import Question JSON

Current Question (ID: 20981)

Question:
$\text{Which of the following species has an odd number of electrons?}$
Options:
  • 1. $\text{NO}_2$
  • 2. $\text{N}_2\text{O}$
  • 3. $\text{N}_2\text{O}_3$
  • 4. $\text{N}_2\text{O}_5$
Solution:
$\text{Hint: If a molecule contains an odd number of electrons then it is called odd e}^- \text{ species}$ $\text{The number of electrons in the given compounds is as follows:}$ $\begin{array}{|c|c|} \hline \text{Species} & \text{Total e}^- \\ \hline \text{NO}_2 & 23 \\ \text{N}_2\text{O} & 22 \\ \text{N}_2\text{O}_3 & 38 \\ \text{N}_2\text{O}_5 & 54 \\ \hline \end{array}$ $\text{The NO}_2 \text{ has an odd number of electrons hence, it is an odd e}^- \text{ species.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}