Import Question JSON

Current Question (ID: 20987)

Question:

$\text{The correct statement among the following is:}$ $1.\ \text{When a covalent bond is formed, transfer of electrons takes place}$ $2.\ \text{Pure } \text{H}_2\text{O does not contain any ion}$ $3.\ \text{A bond is formed when attractive forces overcome repulsive forces}$ $4.\ \text{HF is less polar than HBr}$

Options:

1. $\text{When a covalent bond is formed, transfer of electrons takes place}$
2. $\text{Pure } \text{H}_2\text{O does not contain any ion}$
3. $\text{A bond is formed when attractive forces overcome repulsive forces}$
4. $\text{HF is less polar than HBr}$

Solution:

$\text{Hint: When two atoms approached then attractive force must be greater than repulsive force.}$ $\text{Explanation:}$ $\text{a. When a covalent bond is formed, sharing of electrons takes place.}$ $\text{Covalent bonds involve the sharing of electron pairs between atoms to achieve a stable electron configuration, often fulfilling the octet rule (having eight electrons in the outer shell).}$ $\text{b. Pure water undergoes a very small degree of self-ionization, producing a small amount of } \text{H}^+ \text{ and } \text{OH}^- \text{ ions.}$ $\text{However, the concentration of these ions in pure water is extremely low compared to the number of water molecules.}$ $\text{c. HF is more polar than HBr because F is more electronegative than Br.}$ $\text{The more electronegative an element is, the more polar the bond is.}$ $\text{The correct statement among all the given options is given below:}$ $\text{A bond is formed when attractive forces } (n_1 \leftrightarrow e_2, n_2 \leftrightarrow e_1) \text{ overcomes or balance is established with repulsive force } (n_1 \leftrightarrow n_2, e_1 \leftrightarrow e_2).$ $\text{Hence, option 3 is the correct answer.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}