Import Question JSON

Current Question (ID: 21011)

Question:

$\text{Match the compounds given in } \text{Column-I} \text{ with their respective}$ $\text{hybridisation which is given in } \text{Column-II.}$ $\begin{array}{|c|c|} \hline \text{Column-I (Compound)} & \text{Column-II Hybridisation} \\ \hline (i) \ \text{PCl}_5 & (a) \ sp^3d^2 \\ (ii) \ [\text{Pt(CN)}_4]^{-2} & (b) \ sp^3d \\ (iii) \ [\text{Co(NH}_3)_6]^{3+} & (c) \ d^2sp^3 \\ (iv) \ \text{BrF}_5 & (d) \ dsp^2 \\ \hline \end{array}$ $\text{Correct matching is:}$

Options:

1. $\begin{array}{cccc} \text{I} & \text{II} & \text{III} & \text{IV} \\ \text{b} & \text{d} & \text{c} & \text{a} \end{array}$
2. $\begin{array}{cccc} \text{I} & \text{II} & \text{III} & \text{IV} \\ \text{a} & \text{b} & \text{c} & \text{d} \end{array}$
3. $\begin{array}{cccc} \text{I} & \text{II} & \text{III} & \text{IV} \\ \text{b} & \text{d} & \text{a} & \text{c} \end{array}$
4. $\begin{array}{cccc} \text{I} & \text{II} & \text{III} & \text{IV} \\ \text{d} & \text{b} & \text{a} & \text{c} \end{array}$

Solution:

$\text{The correct matching is:}$ $\text{(i) } \text{PCl}_5 \rightarrow \ sp^3d \ (b)$ $\text{(ii) } [\text{Pt(CN)}_4]^{-2} \rightarrow \ dsp^2 \ (d)$ $\text{(iii) } [\text{Co(NH}_3)_6]^{3+} \rightarrow \ d^2sp^3 \ (c)$ $\text{(iv) } \text{BrF}_5 \rightarrow \ sp^3d^2 \ (a)$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}