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Current Question (ID: 21046)

Question:
$\text{The internal energy change when a system goes from state A to B is 40 kJ/mol.}$ $\text{If the system goes from A to B by a reversible path and returns to state A by an irreversible path, what would be the net change in internal energy?}$
Options:
  • 1. $40 \text{ kJ}$
  • 2. $> 40 \text{kJ}$
  • 3. $< 40 \text{ kJ}$
  • 4. $\text{zero}$
Solution:
$\text{Hint: Internal energy is a state function.}$ $\text{If the system goes from A to B by a reversible path and returns to state A by an irreversible path, it is a cyclic process.}$ $\text{For cyclic process } \Delta E = 0.$ $\text{The } \Delta E \text{ is a state function that only depends on the initial and final position.}$ $\text{For cyclic process, the initial and final position is same, hence } \Delta E = 0.$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}