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Current Question (ID: 21051)

Question:
$\text{The correct match for the following options is:}$ $\begin{array}{|c|c|} \hline \text{List I} & \text{List II} \\ \hline \text{(A) Adiabatic} & \text{(P) } \Delta T = 0 \\ \text{(B) Isothermal} & \text{(Q) Heat exchange is zero} \\ \text{(C) Isochoric} & \text{(R) } \Delta P = 0 \\ \text{(D) Isobaric} & \text{(S) Work done is zero} \\ \hline \end{array}$
Options:
  • 1. $\text{A} \rightarrow \text{Q}, \text{B} \rightarrow \text{P}, \text{C} \rightarrow \text{S}, \text{D} \rightarrow \text{R}$
  • 2. $\text{A} \rightarrow \text{P}, \text{B} \rightarrow \text{Q}, \text{C} \rightarrow \text{R}, \text{D} \rightarrow \text{S}$
  • 3. $\text{A} \rightarrow \text{S}, \text{B} \rightarrow \text{R}, \text{C} \rightarrow \text{Q}, \text{D} \rightarrow \text{P}$
  • 4. $\text{A} \rightarrow \text{P}, \text{B} \rightarrow \text{R}, \text{C} \rightarrow \text{S}, \text{D} \rightarrow \text{Q}$
Solution:
$\text{Hint: There is no temperature change for isothermal process.}$ $\text{Explanation:}$ $(i) \text{Adiabatic process: An adiabatic process is a type of thermodynamic process that occurs without transferring heat between the thermodynamic system and its environment. Thus, heat exchange is zero in adiabatic process.}$ $(ii) \text{Isothermal process: An isothermal process is a type of thermodynamic process in which the temperature } T \text{ of a system remains constant; or } \Delta T = 0.$ $(iii) \text{Isochoric process: An isochoric process, also called a constant-volume process, is a thermodynamic process during which the volume of the closed system undergoing such a process remains constant.}$ $\Delta V = 0, \ w = -P \Delta V$ $\text{So, work done is zero in isochoric process.}$ $(iv) \text{Isobaric process: An isobaric process is a type of thermodynamic process in which the pressure of the system stays constant; or } \Delta P = 0.$ $\text{So, option 1 is the correct answer.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}