Import Question JSON

Current Question (ID: 21057)

Question:

$\text{Given below are two statements:}$ $\text{Statement I:}$ $\text{According to Lewis's concept, H}_2\text{O acts as an amphoteric substance.}$ $\text{Statement II:}$ $\text{H}_2\text{O act as an acid on reaction with NH}_3, \text{ while it acts as a base on reaction with H}_2\text{S.}$ $\text{In light of the above statements choose the correct answer from the options given below:}$

Options:

1. $\text{Both Statement I and Statement II are correct.}$
2. $\text{Both Statement I and Statement II are incorrect.}$
3. $\text{Statement I is correct and Statement II is incorrect.}$
4. $\text{Statement I is incorrect and Statement II is correct.}$

Solution:

$\text{Hint: According to Lewis's concept water act as a Base.}$ $\text{According to Lewis's concept acid are a species that accepts an electron pair and a base that donates an electron pair.}$ $\text{Water is an amphoteric compound because it reacts with both acid as well as a base. According to the Brönsted-Lowry theory, water is an amphoteric compound.}$ $\text{The reaction is as follows:}$ $\text{H}_2\text{S(aq) + H}_2\text{O(l)} \rightleftharpoons \text{H}_3\text{O}^+(aq) + \text{SH}^-(aq)}$ $\text{Here, water acts as a base.}$ $\text{NH}_3 + \text{H}_2\text{O} \rightleftharpoons \text{NH}_4^+ + \text{OH}^-}$ $\text{Thus, water acts as an acid.}$ $\text{Thus, statement-I is false while statement-II is true.}$ $\text{The correct option is the fourth option.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}