Import Question JSON

Current Question (ID: 21091)

Question:

$\text{Consider the following statements}$ $\text{a. The correct order of increasing acidic strength is } \text{CH}_4 < \text{NH}_3 < \text{HF} < \text{H}_2\text{O.}$ $\text{b. The ionic product of water is temperature dependent.}$ $\text{c. A monobasic acid with } K_a = 10^{-5} \text{ has a pH = 5. The degree of dissociation of this acid is 50\%.}$ $\text{The correct statements are:}$

Options:

1. $(\text{a}) \text{ and } (\text{b})$
2. $(\text{a}), (\text{b}) \text{ and } (\text{c})$
3. $(\text{b}) \text{ and } (\text{c})$
4. $(\text{a}) \text{ and } (\text{c})$

Solution:

$\text{Statement (a): The correct order of increasing acidic strength should be:}$ $\text{CH}_4 < \text{NH}_3 < \text{H}_2\text{O} < \text{HF}$ $\text{because HF is more acidic than H}_2\text{O due to its higher electronegativity, and H}_2\text{O is more acidic than NH}_3 \text{ and CH}_4. \text{So, Statement (a) is incorrect.}}$ $\text{Statement (b): The ionic product of water (} K_w \text{) is indeed temperature dependent. As temperature increases, } K_w \text{ increases due to greater ionization. Therefore, Statement (b) is correct.}$ $\text{(c) pH = 5}$ $\therefore [\text{H}^+] = c\alpha = 10^{-5}$ $K_a = \frac{c\alpha^2}{(1-\alpha)}$ $k_a = \frac{[\text{H}^+]\alpha}{(1-\alpha)}$ $10^{-5} = \frac{10^{-5} \times \alpha}{1-\alpha}$ $\Rightarrow 1 = 2\alpha$ $\therefore \alpha = 0.5$ $\text{When pH = pKa, the acid is 50\% dissociated, the acid is 50\% dissociated.}$ $\text{Therefore, Statement (c) is correct.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}