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Current Question (ID: 21125)

Question:
$\text{In a closed reaction vessel, Phosphorus pentachloride dissociates as follows:}$ $\text{PCl}_5(g) \rightleftharpoons \text{PCl}_3(g) + \text{Cl}_2(g)$ $\text{If the total pressure at equilibrium of the reaction mixture is } P \text{ and the degree of dissociation of PCl}_5 \text{ is } x, \text{ the partial pressure of PCl}_3 \text{ will be:}$
Options:
  • 1. $\left( \frac{x}{x+1} \right) P$
  • 2. $\left( \frac{2x}{x-1} \right) P$
  • 3. $\left( \frac{x}{x-1} \right) P$
  • 4. $\left( \frac{x}{1-x} \right) P$
Solution:
$\text{Hint: Use Dalton law of partial pressure formula}$ $\text{PCl}_5(g) \rightleftharpoons \text{PCl}_3(g) + \text{Cl}_2(g)$ $\text{Total number of moles at equilibrium}$ $= (1-x) + x + x$ $= 1 + x$ $\text{The formula of partial pressure is as follows:}$ $P = P_{\text{Total}}X$ $P_{\text{PCl}_3} = \left[ \frac{x}{1+x} \right] \times P$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}