Import Question JSON

Current Question (ID: 21127)

Question:

$\text{The exothermic formation of ClF}_3 \text{ is represented by the equation:}$ $\text{Cl}_2(g) + 3\text{F}_2(g) \rightleftharpoons 2 \text{ClF}_3(g); \quad \Delta H_r = -329 \text{ kJ}$ $\text{Which of the following will increase the quantity of ClF}_3 \text{ in an}$ $\text{equilibrium mixture of Cl}_2, \text{ F}_2, \text{ and ClF}_3?$

Options:

1. $\text{Adding F}_2$
2. $\text{Increasing the volume of the container}$
3. $\text{Removing Cl}_2$
4. $\text{Increasing the temperature}$

Solution:

$\text{Hint: If reaction proceed in forward direction then concentration of ClF}_3 \text{ increases.}$ $1. \text{ The reaction is an example of an exothermic reaction. If the}$ $\text{forward reaction is exothermic then the backward reaction is}$ $\text{endothermic and on increasing the temperature backward reaction is}$ $\text{favored. Thus, ClF}_3 \text{ concentration decreases.}$ $2. \text{ Removing Cl}_2 \text{ decreases the concentration of Cl}_2 \text{ thus, the reaction}$ $\text{will proceed in a backward direction so that Cl}_2 \text{ concentration}$ $\text{increases. Thus, ClF}_3 \text{ concentration decreases.}$ $3. \text{ The volume is inversely proportional to pressure hence volume}$ $\text{increases the pressure is decreases. Hence, reaction will proceed in}$ $\text{the direction where number of mole is high. Thus in backward}$ $\text{direction.}$ $4. \text{ Adding F}_2 \text{ will increases the concentration of reactant thus}$ $\text{reaction will proceed in forward direction. The concentration of}$ $\text{ClF}_3 \text{ increases.}$ $\text{Thus, option first is the correct answer.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}