Import Question JSON

Current Question (ID: 21133)

Question:
$\text{Consider the reaction equilibrium:}$ $2\text{SO}_2(g) + \text{O}_2(g) \rightleftharpoons 2\text{SO}_3(g); \quad \Delta H^\circ = -198 \text{ kJ}$ $\text{On the basis of Le-Chatelier's principle, the condition favorable for the forward reaction is:}$
Options:
  • 1. $\text{lowering of temperature as well as pressure}$
  • 2. $\text{increasing temperature as well as pressure}$
  • 3. $\text{lowering the temperature and increasing the pressure}$
  • 4. $\text{Any value of temperature and pressure}$
Solution:
$\text{Hint: Forward reaction is exothermic in nature}$ $\text{The reaction is an example of an exothermic reaction. Lower the temperature favors a forward reaction.}$ $\text{The backward reaction is an endothermic reaction hence, increasing the temperature favors the backward reaction.}$ $\text{For the given reaction, the } \Delta n_g \text{ value is negative. Hence if pressure increases the reaction will go at the forward direction.}$ $\text{Thus, option third is the correct answer.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}