Import Question JSON

Current Question (ID: 21158)

Question:

$\text{The pH of the solution obtained by mixing 600 mL of 0.04 M HCl and 400 mL of 0.02 M H}_2\text{SO}_4 \text{ is:}$ $[\log 4 = 0.6]$

Options:

1. $3.4$
2. $5.4$
3. $1.4$
4. $2.4$

Solution:

$\text{moles of H}^+ \text{ from HCl} = 0.04 \times 600 = 24 \text{ mol}$ $\text{moles of H}^+ \text{ from H}_2\text{SO}_4 = 0.02 \times 2 \times 400 = 16 \text{ mol}$ $\text{Total moles of H}^+ = 24 + 16 = 40 \text{ mol}$ $\text{Final volume of solution} = 1000 \text{ mL}$ $[\text{H}^+] = \frac{40}{1000} = 0.04 \text{ M}$ $\text{pH} = -\log(0.04) = 1.4$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}