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Current Question (ID: 21178)

Question:

$\text{The oxidation states of iron atoms in compounds (A), (B) and (C), respectively, are } x, y \text{ and } z. \text{ The sum of } x, y \text{ and } z \text{ is} \underline{\phantom{answer}}.$ $\text{Na}_4[\text{Fe(CN)}_5\text{NOS}] \quad \text{Na}_4[\text{FeO}_4] \quad [\text{Fe}_2(\text{CO})_9]$

Options:

1. 4
2. 5
3. 6
4. 7

Solution:

$\text{Hint: The oxidation state of Fe in } \text{Fe}_2(\text{CO})_9 \text{ is zero.}$ $\text{Calculate the oxidation state of Fe in all three compounds as follows:}$ $(A) \quad \text{Na}_4[\text{Fe(CN)}_5(\text{NOS})]$ $(+1)4 + x + (-1)5 + (-1)1 = 0$ $x = +2$ $(B) \quad \text{Na}_4[\text{FeO}_4]$ $(+1)4 + y + (-2)4 = 0$ $y = +4$ $(C) \quad [\text{Fe}_2(\text{CO})_9]$ $2z + 0 \times 9 = 0$ $z = 0$ $\text{The value of } X, Y, \text{ and } Z \text{ are } 2, 4, \text{ and } 0 \text{ respectively.}$ $\text{Hence, the sum of } X, Y \text{ and } Z \text{ is } 2 + 4 + 0 \text{ is } 6.$ $\text{Sodium ferrate(IV), } \text{Na}_4\text{FeO}_4, \text{ is highly hygroscopic and decomposes to } \text{Fe(VI) and Fe(III) upon contact with water.}$ $3\text{Na}_4\text{FeO}_4 + 5\text{H}_2\text{O} \rightarrow \text{Na}_2\text{FeO}_4 + \text{Fe}_2\text{O}_3 + 10\text{NaOH}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}