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Current Question (ID: 21180)

Question:

$\text{The reaction of sulphur in an alkaline medium is given below:}$ $\text{S}_8{(s)} + a\text{OH}^-_{(aq)} \rightarrow b\text{S}^{2-}_{(aq)} + c\text{S}_2\text{O}_3^{2-}_{(aq)} + d\text{H}_2\text{O}_{(\ell)}$ $\text{The value of 'a' is:}$

Options:

1. $10$
2. $12$
3. $14$
4. $17$

Solution:

$\text{Hint: Sulphur in } \text{S}_8 \text{ undergoes disproportionation reaction.}$ $\text{Step 1:}$ $\text{Calculate the total number of electron exchanges that take place}$ $\text{Step 2:}$ $\text{for balancing in basic medium add equal number of } \text{OH}^- \text{ that of } \text{H}^+$ $2\text{S}_8 + 12\text{H}_2\text{O} + 24\text{OH}^- \rightarrow 8\text{S}^{2-} + 4\text{S}_2\text{O}_3^{2-} + 24\text{H}_2\text{O}$ $2\text{S}_8 + 24\text{OH}^- \rightarrow 8\text{S}^{2-} + 4\text{S}_2\text{O}_3^{2-} + 12\text{H}_2\text{O}$ $\text{S}_8 + 12\text{OH}^- \rightarrow 4\text{S}^{2-} + 2\text{S}_2\text{O}_3^{2-} + 6\text{H}_2\text{O}$ $a = 12$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}