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Current Question (ID: 21181)

Question:
$\text{Given that:}$ $E^\Theta_{\text{O}_2/\text{H}_2\text{O}} = +1.23 \text{ V}; \ E^\Theta_{\text{S}_2\text{O}_8^{2-}/\text{SO}_4^{2-}} = 2.05 \text{ V}$ $E^\Theta_{\text{Br}_2/\text{Br}^-} = +1.09 \text{ V}; \ E^\Theta_{\text{Au}^{3+}/\text{Au}} = +1.4 \text{ V}$ $\text{Which of the following is the strongest oxidizing agent?}$
Options:
  • 1. $\text{S}_2\text{O}_8^{2-}$
  • 2. $\text{O}_2$
  • 3. $\text{Au}^{3+}$
  • 4. $\text{Br}_2$
Solution:
$\text{Hint: Higher is the reduction potential value, higher will be}$ $\text{The strongest oxidizing agents are those species that oxidised other}$ $\text{and themselves gets reduced. Thus, the species having a high}$ $\text{reduction potential value is the strong oxidizing agent.}$ $\text{The } \text{S}_2\text{O}_8^{2-} \text{ has the highest reduction potential value thus, it is a}$ $\text{strongest oxidizing agent.}$ $\text{Thus, option first is the correct answer.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}