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Current Question (ID: 21184)

Question:

$\text{Consider the following reaction:}$ $a\text{Cu} + b\text{HNO}_3 \rightarrow c\text{Cu(NO}_3\text{)}_2 + d\text{NO} + e\text{H}_2\text{O}$ $\text{The values of } a, b, \text{ and } e \text{ in the reaction are, respectively:}$

Options:

1. $3, 8 \text{ and } 4$
2. $5, 2 \text{ and } 8$
3. $5, 2 \text{ and } 16$
4. $2, 5 \text{ and } 8$

Solution:

$\text{Hint: Use Half Reaction Method for balancing the equation}$ $\text{Cu} + \text{HNO}_3 \rightarrow \text{Cu(NO}_3\text{)}_2 + \text{NO} + \text{H}_2\text{O}$ $\text{The change in oxidation state of Cu is 0 to +2. Change in oxidation state is +2}$ $\text{The oxidation state of nitrogen changes from 5 to +2 in NO. The change in oxidation state is +3.}$ $\text{As all HNO}_3 \text{ molecules do not reduce to NO, a part of it changes to Cu(NO}_3\text{)}_2. \text{ Thus to balance 6 excess } \text{NO}_3^- \text{ ions on the right side of the equation, add 6HNO}_3 \text{ on the left side.}$ $3\text{Cu} + 8\text{HNO}_3 \rightarrow 3\text{Cu(NO}_3\text{)}_2 + 2\text{NO} + \text{H}_2\text{O}$ $\text{Multiple } \text{H}_2\text{O by 4.}$ $3\text{Cu} + 8\text{HNO}_3 \rightarrow 3\text{Cu(NO}_3\text{)}_2 + 2\text{NO} + 4\text{H}_2\text{O}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}