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Current Question (ID: 21188)

Question:

$\text{Standard reduction electrode potentials of three metals A, B and C are } +0.5 \text{ V}, -3.0 \text{ V and } -1.2 \text{ V respectively. The reducing power of these metals are:}$

Options:

1. $\text{B} > \text{C} > \text{A}$
2. $\text{A} > \text{B} > \text{C}$
3. $\text{C} > \text{B} > \text{A}$
4. $\text{A} > \text{C} > \text{B}$

Solution:

$\text{Hint: More negative value of } E^0 \text{ means larger reducing power}$ $\text{High the reduction potential value lower will be the reducing power.}$ $\text{The given values are as follows:}$ $\text{A, B and C are } +0.5 \text{ V}, -3.0 \text{ V and } -1.2 \text{ V respectively.}$ $\text{The decreasing order of reduction potential value is as follows:}$ $\text{A} > \text{C} > \text{B}$ $\text{The reducing power order is } \text{A} < \text{C} < \text{B}$ $\text{reducing potential and reducing power are inversely related.}$ $\text{A substance with high reducing potential is a good oxidizing agent (weak reducing power), while a substance with high reducing power has a low reducing potential and acts as a strong reducing agent.}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}