Import Question JSON

Current Question (ID: 21199)

Question:
$\text{The correct statement about } \text{B}_2\text{H}_6 \text{ is:}$
Options:
  • 1. $\text{The terminal B--H bonds have less p-character when compared to bridging bonds.}$
  • 2. $\text{The two B--H--B bonds are not of the same length.}$
  • 3. $\text{All B--H--B angles are } 120^\circ.$
  • 4. $\text{Its fragment, BH}_3, \text{ behaves as a Lewis base.}$
Solution:
$\theta_2 > \theta_1, \therefore \text{B--H (terminal) has less p-character as compared to the bridge bond.}$ $\text{Both B--H--B bridge bonds have the same bond length.}$ $\text{B--H--B bond angle is } \approx 90^\circ, \text{ not } 120^\circ$ $\text{The octet of B in BH}_3 \text{ is not completed hence, BH}_3 \text{ is e-deficient species and therefore acts as lewis acid.}$ $\text{Hence, option one is the answer}$ $\text{The bond angle of terminal bonds is more than the bond angle of bridge bonds.}$ $\text{It means that terminal bond electrons lie farther from the nucleus than the electrons of the bridge bonds.}$ $\text{We know that p-orbitals lie farther from the nucleus than the s-orbitals.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}