Import Question JSON

Current Question (ID: 21201)

Question:

$\text{Diborane (B}_2\text{H}_6\text{) reacts independently with O}_2 \text{ and H}_2\text{O to produce, respectively:}$ $\text{1. H}_3\text{BO}_3 \text{ and B}_2\text{O}_3}$ $\text{2. B}_2\text{O}_3 \text{ and H}_3\text{BO}_3}$ $\text{3. B}_2\text{O}_3 \text{ and [BH}_4\text{]}^-}$ $\text{4. HBO}_2 \text{ and H}_3\text{BO}_3}$

Options:

1. $\text{H}_3\text{BO}_3 \text{ and B}_2\text{O}_3$
2. $\text{B}_2\text{O}_3 \text{ and H}_3\text{BO}_3$
3. $\text{B}_2\text{O}_3 \text{ and [BH}_4\text{]}^-$
4. $\text{HBO}_2 \text{ and H}_3\text{BO}_3$

Solution:

$\text{Diborane is a highly reactive and versatile substance which has numerous applications.}$ $\text{Hence we come to know that diborane reacts exothermically with oxygen to form boron trioxide and water.}$ $\text{It reacts violently with water and produces hydrogen and boric acid.}$ $\text{The reaction of B}_2\text{H}_6 \text{ with O}_2 \text{ as follows:}$ $2 \text{B}_2\text{H}_6 + 6 \text{O}_2 \rightarrow 2 \text{B}_2\text{O}_3 + 6 \text{H}_2\text{O}$ $\text{Boranes are readily hydrolysed by water to give boric acid.}$ $\text{The reaction is as follows:}$ $\text{B}_2\text{H}_6 + \text{H}_2\text{O} \rightarrow \text{H}_3\text{BO}_3$ $\text{Boric acid, on heating, loses water in three different stages at different temperatures ultimately giving boron trioxide or boric anhydride.}$ $\text{Boric acid is widely used as an antiseptic for the treatment of minor cuts and burns.}$ $\text{Furthermore, this compound is also used in medical dressings and salves.}$ $\text{Very dilute solutions of boric acid can be used as an eyewash.}$ $\text{So, option 2 is the correct answer.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}