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Current Question (ID: 21206)

Question:

$\text{In view of the signs of } \Delta_r G^\circ \text{ for the following reactions:}$ $\text{PbO}_2 + \text{Pb} \rightarrow 2 \text{PbO}, \Delta_r G^\circ < 0$ $\text{SnO}_2 + \text{Sn} \rightarrow 2 \text{SnO}, \Delta_r G^\circ > 0$ $\text{The oxidation states more characteristic for lead and tin are respectively:}$

Options:

1. $\text{For lead } +2, \text{ for tin } +2$
2. $\text{For lead } +4, \text{ for tin } +4$
3. $\text{For lead } +2, \text{ for tin } +4$
4. $\text{For lead } +4, \text{ for tin } +2$

Solution:

$\text{Hint: If } \Delta_r G^\circ \text{ value is negative then reaction is spontaneous.}$ $\text{If } \Delta_r G^\circ \text{ value is negative then reaction is spontaneous. In the first reaction, the } \Delta_r G^\circ \text{ value is negative hence, it indicates that PbO}_2 \text{ is less stable than PbO.}$ $\text{Hence, } +4 \text{ oxidation state of PbO}_2 \text{ is less stable than } +2 \text{ oxidation state in PbO.}$ $\text{In the second reaction, the } \Delta_r G^\circ \text{ value is positive hence, it indicates that SnO}_2 \text{ is more stable than SnO. Hence, } +2 \text{ oxidation state of SnO is less stable than } +4 \text{ oxidation state in SnO}_2.$ $\text{Thus, option third is the correct answer.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}