Import Question JSON

Current Question (ID: 21208)

Question:

$\text{Graphite is a soft solid lubricant extremely difficult to melt. The reason for this anomalous behavior is that graphite:}$

Options:

1. $\text{is a non-crystalline substance.}$
2. $\text{is an allotropic form of diamond.}$
3. $\text{has molecules of variable molecular masses like polymers.}$
4. $\text{has carbon atoms arranged in large plates of rings of strongly bound carbon atoms with weak interplate bonds.}$

Solution:

$\text{Hint: In graphite, layers can slide one over the other.}$ $\text{Explanation:}$ $\text{Graphite is a crystalline form of the element carbon. It consists of stacked layers of graphene. Graphite occurs naturally and is the most stable form of carbon under standard conditions.}$ $\text{Graphite is a soft solid lubricant extremely difficult to melt. The reason for this anomalous behavior is that graphite has carbon atoms arranged in large plates of rings of strongly bound carbon atoms with weak interplate bonds.}$ $\text{Graphite has a layered structure that consists of rings of six carbon atoms arranged in widely spaced horizontal sheets. Graphite thus crystallizes in the hexagonal system, in contrast to the same element crystallizing in the octahedral or tetrahedral system as diamond.}$ $\text{Graphite cleaves easily between the layers and, therefore, is very soft and slippery. It is thermodynamically the most stable form of carbon. Its standard enthalpy of formation is thus taken as zero.}$ $\text{Thus, option 4th is the correct answer.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}