Import Question JSON

Current Question (ID: 21209)

Question:

$\text{Assertion (A): Carbon forms two oxides } \text{CO} \text{ and } \text{CO}_2 \text{ where } \text{CO} \text{ is neutral whereas } \text{CO}_2 \text{ is acidic.}$ $\text{Reason (R): } \text{CO}_2 \text{ will combine with water to give carbonic acid and } \text{CO} \text{ is soluble in water.}$

Options:

1. $\text{Both (A) and (R) are True and (R) is the correct explanation of (A).}$
2. $\text{Both (A) and (R) are True but (R) is not the correct explanation of (A).}$
3. $\text{(A) is True but (R) is False.}$
4. $\text{Both (A) and (R) are False.}$

Solution:

$\text{CO}_2 \text{ will form carbonic acid with water and it is acidic in nature while CO is neutral but there is no relation of neutrality with solubility.}$ $\text{H}_2\text{O} + \text{CO}_2 \leftrightarrow \text{H}_2\text{CO}_3$ $\text{Hence, both reason and assertion are correct but reason is not the correct explanation of assertion.}$ $\text{The solubility of CO in water at } 25^\circ\text{C and } 1 \text{ atm is about } 0.025 \text{ g per } 100 \text{ mL of water, which is quite low.}$ $\text{So, option 2 is the correct answer.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}