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Current Question (ID: 21211)

Question:

$\text{Given below are two statements:}$ $\text{Statement I:}$ \text{Gallium (Ga) has a low melting point, so it is used in thermometers.}$ $\text{Statement II:}$ \text{A substance having a melting point of 253 K can be measured by a Gallium thermometer.}$

Options:

1. $\text{Statement I is false but Statement II is true.}$
2. $\text{Both Statement I and Statement II are false.}$
3. $\text{Both Statement I and Statement II are true.}$
4. $\text{Statement I is true but Statement II is false.}$

Solution:

$\text{Hint: Gallium (Ga) has a very low melting point (~29.76}^\circ\text{C or 302.91 K).}$ $\text{Statement I: Gallium (Ga) has a very low melting point (~29.76}^\circ\text{C or 302.91 K). Due to this property, it can be used in high-temperature thermometers as it remains in the liquid state over a wide temperature range. Thus, Statement I is true.}$ $\text{Statement II: If a substance is at 253 K (or -20}^\circ\text{C), it is below the melting point of gallium (~30}^\circ\text{C). Since gallium would be solid at this temperature, it cannot function properly in a thermometer. Thus, Statement II is false.}$ $\text{For a thermometer, the melting point (MP) is the key factor, not the boiling point (BP).}$ $\text{Why is MP More Important?}$ $\text{A thermometer's liquid must remain in a fluid state over the range of temperatures it measures.}$ $\text{If a substance solidifies, it cannot function as a liquid column, making it useless as a thermometer liquid.}$ $\text{Gallium melts at 303 K (30}^\circ\text{C), so it cannot measure temperatures below this point because it would be solid.}$ $\text{The boiling point (BP) is relevant for upper temperature limits but not as crucial as the MP for everyday thermometers.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}