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Current Question (ID: 21222)

Question:

$\text{If } 0.450 \text{ grams of an organic compound containing Carbon, Hydrogen }$ $\text{and Oxygen on complete combustion gives } 0.735 \text{ grams CO}_2 \text{ and } 0.45$ $\text{grams of water, then the mass \% of oxygen in the compound is:}$ $\text{(Report your answer to the nearest integer)}$

Options:

1. $31$
2. $49$
3. $44$
4. $51$

Solution:

$\text{Step 1: The reaction of combustion of the given compound is:}$ $\text{C}_x\text{H}_y\text{O}_z + \text{O}_2 (g) \rightarrow \text{CO}_2 (g) + \text{H}_2\text{O}(g)$ $\text{The given mass of the organic compound is: } 0.450 \text{ g}$ $\text{The given mass of } \text{CO}_2 = 0.735 \text{ g}$ $\text{and the given mass of } \text{H}_2\text{O} = 0.45 \text{ g}$ $\text{This question aims to calculate the mass \% of oxygen in the given}$ $\text{compound.}$ $\text{Step 2: } 44 \text{ g of } \text{CO}_2 \text{ contains } 12 \text{ g of carbon}$ $0.735 \text{ g of } \text{CO}_2 \text{ contains } \frac{0.735 \text{ g}}{44 \text{ g}} \times 12 \text{ g} = 0.20 \text{ g of carbon}$ $18 \text{ g of } \text{H}_2\text{O} \text{ contains } 2 \text{ g of hydrogen}$ $0.45 \text{ g of } \text{H}_2\text{O} \text{ contains } \frac{0.45 \text{ g}}{18} \times 2 \text{ g} = 0.05 \text{ g of hydrogen}$ $\text{The total mass of carbon and hydrogen is } (0.20 + 0.05) \text{ g} = 0.25 \text{ g}$ $\text{Step 3: The mass of oxygen will be: } (0.45 - 0.25) \text{ g} = 0.20 \text{ g}$ $\text{The mass \% of oxygen can be calculated as:}$ $\frac{\text{mass of the oxygen in the compound}}{\text{mass of the compound}} \times 100$ $\text{The mass \% of oxygen} = \frac{0.20 \text{ g}}{0.45 \text{ g}} \times 100 = 44.44\%$ $\text{Hence, option 3 is the correct answer.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}