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Current Question (ID: 21226)

Question:
$\text{The false statement among the following is:}$
Options:
  • 1. $\text{Carius tube is used in the estimation of sulphur in an organic compound}$
  • 2. $\text{Carius method is used for the estimation of nitrogen in an organic compound}$
  • 3. $\text{Phosphoric acid produced on oxidation of phosphorus present in an organic compound is precipitated as Mg}_2\text{P}_2\text{O}_7 \text{ by adding magnesia mixture.}$
  • 4. $\text{Kjeldahl's method is used for the estimation of nitrogen in an organic compound}$
Solution:
$\text{Hint: Carius method is used for the estimation of halogen in an organic compound}$ $\text{The correct statements are as follows:}$ $\text{1.}$ $\text{Carius tube is used in the estimation of sulphur in organic compounds. A known mass of an organic compound is heated in a Carius tube with sodium peroxide or fuming nitric acid. Sulphur present in the compound is oxidised to sulphuric acid.}$ $\text{It is precipitated as barium sulphate by adding an excess of barium chloride solution in water.}$ $\text{2.}$ $\text{Carius method is used for the estimation of nitrogen in an organic compound is a false statement. It is used for the estimation of halogen.}$ $\text{3.}$ $\text{A known mass of an organic compound is heated with fuming nitric acid whereupon phosphorus present in the compound is oxidised to phosphoric acid. Then phosphoric acid is precipitated as MgNH}_4\text{PO}_4 \text{ by adding magnesia mixture which on ignition yields Mg}_2\text{P}_2\text{O}_7.}$ $\text{4.}$ $\text{Kjeldahl's method is used for the estimation of nitrogen in an organic compound}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}