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Current Question (ID: 21231)

Question:

$\text{The Kjeldahl method of Nitrogen estimation fails for which of the following reaction products?}$ $\begin{array}{cc} \text{1.} & \text{2.} \\ \text{NO}_2 & \text{CN} \\ \text{Sn/HCl} & \text{LiAlH}_4 \\ \text{3.} & \text{4.} \\ \text{CH}_2\text{CN} & \text{NH}_2 \\ \text{(i) SnCl}_4 + \text{HCl} & \text{NaNO}_2, \text{HCl} \\ \text{(ii) H}_2\text{O} & \end{array}$

Options:

1. $(a), (c) \text{ and } (d)$
2. $(b) \text{ and } (c)$
3. $(a) \text{ and } (d)$
4. $(c) \text{ and } (d)$

Solution:

$\text{Hint: Compounds containing nitrogen in nitro and azo groups and nitrogen present in the ring (e.g. pyridine) as nitrogen, is not applicable.}$ $\text{Kjeldahl method is not applicable to compounds containing nitrogen in nitro and azo groups and nitrogen present in the ring (e.g. pyridine)}$ $\text{as nitrogen of these compounds does not change to ammonium.}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}