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Current Question (ID: 21236)

Question:
$\text{The IUPAC name of the following compound is -}$ $\begin{array}{c} \text{H}_3\text{C} \quad \text{OH} \\ | \\ \text{H}_3\text{C} - \text{C} - \text{C} - \text{C} - \text{C} \\ | \\ \text{H} \quad \text{H}_2 \quad \text{O} \\ | \\ \text{OH} \end{array}$
Options:
  • 1. $4,4\text{-Dimethyl-3-hydroxybutanoic acid}$
  • 2. $2\text{-Methyl-3-hydroxypentan-5-oic acid}$
  • 3. $4\text{-Methyl-3-hydroxypentanoic acid}$
  • 4. $3\text{-Hydroxy-4-methylpentanoic acid}$
Solution:
$\text{Hint: Parent chain name is pentanoic acid}$ $\text{In the given compound parent chain contains 5 carbon atoms and}$ $\text{COOH group carbon gets high priority and least position. The}$ $\text{compound with numbering system is as follows:}$ $\begin{array}{c} \text{CH}_3 - \text{CH} - \text{CH} - \text{CH}_2 - \text{COOH} \\ 5 \quad 4 \quad 3 \quad 2 \quad 1 \\ \text{CH}_3 \quad \text{OH} \end{array}$ $\text{At third position, -OH group is present and at fourth position CH}_3$ $\text{group is present. For -OH group hydroxy is used and for -CH}_3$ $\text{group methyl is used.}$ $\text{The parent chain name is pentanoic acid.}$ $\text{The IUPAC name of the compound is 3-Hydroxy-4-methylpentanoic acid.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}