Import Question JSON

Current Question (ID: 21239)

Question:

$\text{The increasing order of nucleophilicity of the following nucleophiles is:}$ $\begin{array}{ll} (a) & \text{CH}_3\text{CO}_2^- \\ (b) & \text{H}_2\text{O} \\ (c) & \text{CH}_3\text{SO}_3^- \\ (d) & \text{OH}^- \end{array}$

Options:

1. $(b) < (c) < (a) < (d)$
2. $(b) < (c) < (d) < (a)$
3. $(a) < (d) < (c) < (b)$
4. $(d) < (a) < (c) < (b)$

Solution:

$\text{Hint: As electron density increases nucleophilicity of the nucleophile increases.}$ $\text{The neutral compound is less nucleophilic than the anionic compound because electron density in the anionic compound is more than the neutral compound.}$ $\text{Hence, } \text{H}_2\text{O} \text{ is the least nucleophilic in nature. Among } \text{HO}^-, \text{CH}_3\text{COO}^-, \text{ and } \text{CH}_3\text{SO}_3^-, \text{ the hydroxide ion is the strongest nucleophile because in } \text{CH}_3\text{COO}^- \text{, and } \text{CH}_3\text{SO}_3^- \text{ resonance takes place and resonance decreases the electron density in the atom and nucleophilicity of the group decreases.}$ $\text{In } \text{CH}_3\text{COO}^-, \text{ and } \text{CH}_3\text{SO}_3^-, \text{ CH}_3\text{COO}^- \text{ is a better nucleophile than } \text{CH}_3\text{SO}_3^- \text{ because more resonance effect occurs in } \text{CH}_3\text{SO}_3^- \text{ than } \text{CH}_3\text{COO}^-. \text{ Due to this nucleophilicity of } \text{CH}_3\text{SO}_3^- \text{ decreases.}$ $\text{Hence, the increasing order of nucleophilicity of the following nucleophile is as follows:}$ $\text{H}_2\text{O} < \text{CH}_3\text{SO}_3^- < \text{CH}_3\text{COO}^- < \text{OH}^-$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}