Import Question JSON

Current Question (ID: 21247)

Question:
$\text{Given below are four statements about thiol anion (RS}^-\text{) and alkoxy anion (RO}^-\text{).}$ $\text{Which of the following statements is correct?}$
Options:
  • 1. $\text{RS}^- \text{ is less basic but more nucleophilic than RO}^-$
  • 2. $\text{RS}^- \text{ is more basic and more nucleophilic than RO}^-$
  • 3. $\text{RS}^- \text{ is more basic but less nucleophilic than RO}^-$
  • 4. $\text{RS}^- \text{ is less basic and less nucleophilic than RO}^-$
Solution:
$\text{Hint: RS}^- \text{ is more stable than RO}^-.$ $\text{Weak acid has strong conjugate base or vice versa.}$ $\text{The conjugate base of ROH is RO}^- \text{ and conjugate base of RSH is RS}^-.$ $\text{The conjugate base of RSH is more stable than conjugate base of ROH because sulphur can stabilize the negative charge more easily than oxygen.}$ $\text{Oxygen is more electronegative than sulphur hence, it will not easily share its electron with electrophile.}$ $\text{Hence, RS}^- \text{ is less basic but more nucleophilic than RO}^-.$ $\text{Nucleophilic strength depends on the electronegativity of the atom.}$ $\text{Lower the electronegativity of an atom, larger the nucleophilic strength of an atom and more readily it will donate electrons to the electrophilic (e- deficient) species.}$ $\text{Since, electronegativity decreases down the group, thus nucleophilic strength increases down the group,}$ $\text{Hence, RS}^- \text{ is more nucleophilic than RO}^- \text{ due to less electronegativity of S than O.}$ $\text{On the other hand, basic strength of an atom depends upon the tendency to accept a proton more readily.}$ $\text{Since, O-H bond is longer than S-H bond, thus, RO}^- \text{ has a greater tendency to accept a proton than RS}^-.$ $\text{Hence, RO}^- \text{ is a stronger base than RS}^-.$ $\text{Thus, basic strength of the central atom decreases down the group.}$ $\text{Hence, RS}^- \text{ is more nucleophilic but less basic than RO}^-.$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}