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Current Question (ID: 21252)

Question:

$\text{The increasing order of stability of the following free radicals is:}$

Options:

1. $(\text{CH}_3)_2\dot{\text{C}}\text{H} < (\text{CH}_3)_3\dot{\text{C}} < (\text{C}_6\text{H}_5)_2\dot{\text{C}}\text{H} < (\text{C}_6\text{H}_5)_3\dot{\text{C}}$
2. $(\text{C}_6\text{H}_5)_3\dot{\text{C}} < (\text{C}_6\text{H}_5)_2\dot{\text{C}}\text{H} < (\text{CH}_3)_3\dot{\text{C}} < (\text{CH}_3)_2\dot{\text{C}}\text{H}$
3. $(\text{C}_6\text{H}_5)_2\dot{\text{C}}\text{H} < (\text{C}_6\text{H}_5)_3\dot{\text{C}} < (\text{CH}_3)_3\dot{\text{C}} < (\text{CH}_3)_2\dot{\text{C}}\text{H}$
4. $(\text{CH}_3)_2\dot{\text{C}}\text{H} < (\text{CH}_3)_3\dot{\text{C}} < (\text{C}_6\text{H}_5)_3\dot{\text{C}} < (\text{C}_6\text{H}_5)_2\dot{\text{C}}\text{H}$

Solution:

$\text{Hint: Resonance effect is a more powerful effect than hyperconjugation}$ $\text{Free radical stability depends on the effect produced by the side group. If the group shows a resonance effect then free radical is more stable than the free radical which is stabilized by the inductive or hyperconjugation effect.}$ $\text{As the resonance effect increases free radical stability also increases. Free radicals containing three phenyl rings are the most stable free radical.}$ $\text{The order of stability of free radicals is given below:}$ $\text{C}_6\text{H}_5\dot{\text{C}} < \text{C}_6\text{H}_5\dot{\text{C}}\text{H} < \text{C}_6\text{H}_5\dot{\text{C}}\text{H} < \text{C}_6\text{H}_5\dot{\text{C}}\text{H}$ $\text{Highly stable by delocalisation}$ $> \text{CH}_3\dot{\text{C}} > \text{CH}_3\dot{\text{C}}\text{H} > \text{H}_3\text{CC}\dot{\text{C}}\text{H}$ $\text{9-Hyperconjugative Hydrogens and +I effect}$

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{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}