Import Question JSON

Current Question (ID: 21254)

Question:

$\text{The decreasing order of nucleophilicity among the given nucleophiles is:}$ $\begin{array}{cc} \text{(A)} & \text{O} \\ & || \\ & \text{CH}_3\text{C} - \text{O}^- \\ \text{(B)} & \text{CH}_3\text{O}^- \\ \text{(C)} & \text{CN}^- \\ \text{(D)} & \text{O} \\ & || \\ & \text{H}_3\text{C} - \text{S} - \text{O}^- \\ & || \\ & \text{O} \end{array}$

Options:

1. $(\text{C}), (\text{B}), (\text{A}), (\text{D})$
2. $(\text{B}), (\text{C}), (\text{A}), (\text{D})$
3. $(\text{D}), (\text{C}), (\text{B}), (\text{A})$
4. $(\text{A}), (\text{B}), (\text{C}), (\text{D})$

Solution:

$\text{Hint: As the negative charge gets stabilized the nucleophilicity decreases.}$ $\text{Nucleophilicity depends on the negative charge present in the atom.}$ $\text{If the negative charge is more then it is a strong nucleophile and if the}$ $\text{negative charge is less then it is a weak nucleophile.}$ $\text{The electron-withdrawing group stabilizes the negative charge and}$ $\text{decreases the nucleophilicity.}$ $\text{The stability order of a given nucleophile is as follows:}$ $\text{D > A > C > B}$ $\text{D and A is the most stable because of resonance. D is more stable}$ $\text{than A because D forms a more resonating structure than A. C is}$ $\text{more stable than B because the negative charge is formed on sp}$ $\text{carbon.}$ $\text{Ka value of CH}_3\text{OH} = 3.2 \times 10^{-16},$ $\text{Ka value of HCN} = 6.7 \times 10^{-10}$ $\text{The nucleophilicity order is B > C > A > D}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}