Import Question JSON

Current Question (ID: 21259)

Question:

$\text{Given below are two statements:}$ $\text{Statement I:}$ \text{In the Lassaigne test, an organic compound with both N and S, responds to the test of SCN}^-.$ $\text{Statement II:}$ \text{In the Lassaigne test, if Na is taken in excess, it destroys SCN}^- \text{ and forms Na}_2\text{S and NaCN.}$

Options:

1. $\text{Statement I is correct and Statement II is incorrect.}$
2. $\text{Statement I is incorrect and Statement II is correct.}$
3. $\text{Both Statement I and Statement II are correct.}$
4. $\text{Both Statement I and Statement II are incorrect.}$

Solution:

$\text{Hint: In case, nitrogen and sulphur both are present in an organic compound, sodium thiocyanate is formed.}$ $\text{When an organic compound contains both N and S atoms then the organic compound form NaSCN during fusion with sodium.}$ $\text{NaSCN gives blood red colour with neutral FeCl}_3. \text{ The reactions are as follows:}$ $\text{Na + C + N + S} \rightarrow \text{NaSCN}$ $\text{Neutral FeCl}_3 + \text{NaSCN} \rightarrow \text{Fe(SCN)}_3$ $\text{Blood red}$ $\text{If sodium fusion is carried out with an excess of sodium, the thiocyanate decomposes to yield cyanide and sulphide.}$ $\text{These ions give their usual tests. NaSCN + 2Na} \rightarrow \text{NaCN + Na}_2\text{S}$ $\text{Hence, both statements are correct.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}