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Current Question (ID: 21261)

Question:

$\text{In a given organic compound of molar mass}$ $108 \text{ g mol}^{-1}, \text{ C, H, and N atoms are present in a } 9:1:3.5 \text{ by weight ratio.}$ $\text{The molecular formula of the organic compound is:}$

Options:

1. $\text{C}_6\text{H}_8\text{N}_2$
2. $\text{C}_7\text{H}_{10}\text{N}$
3. $\text{C}_5\text{H}_6\text{N}_3$
4. $\text{C}_4\text{H}_{18}\text{N}_3$

Solution:

$\text{Hint: Find number of atoms of each element in the organic compound}$ $\text{Step 1:}$ $\text{Molar mass } 108 \text{ g}$ $\text{Total part by weight } = 9+1+3.5 = 13.5$ $\text{Step 2:}$ $\text{Calculate the number of atoms of each element in the compound}$ $\text{Weight of carbon } = \frac{9}{13.5} \times 108 = 72 \text{ g}$ $\text{Number of carbon atoms } = \frac{72}{12} = 6$ $\text{Weight of hydrogen } = \frac{1}{13.5} \times 108 = 8 \text{ g}$ $\text{Number of hydrogen atoms } = \frac{8}{1} = 8$ $\text{Number of nitrogen atom } = \frac{28}{14} = 2$ $\text{Hence molecular formula } = \text{C}_6\text{H}_8\text{N}_2$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}