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Current Question (ID: 21264)

Question:

$\text{Following types of compounds (as I, II) are studied in terms of isomerism in:}$ $\begin{array}{|c|} \hline \text{(I)} \\ \text{CH}_3\text{CH} = \text{CHCH}_3 \\ \hline \text{(II)} \\ \begin{array}{c} \text{H}_3\text{C} - \text{C} - \text{OH} \\ | \\ \text{H} - \text{C} - \text{CH}_3 \\ | \\ \text{H}_2 \\ \end{array} \\ \hline \end{array}$

Options:

1. $\text{Chain isomerism}$
2. $\text{Position isomerism}$
3. $\text{Conformers}$
4. $\text{Stereoisomerism}$

Solution:

$\text{Hint: If molecule contains a chiral center then it will optically active}$ $\text{Compound first (I) contains a double bond and shows geometrical isomerism. They form cis and trans isomerism.}$ $\text{Compound second (II) contains a chiral center hence they are optically active compound. There mirror images are non superimposable.}$ $\text{The structures are as follows:}$ $\begin{array}{c} \text{CH}_3 - \text{CH} = \text{CH} - \text{CH}_3 \quad \text{and} \quad \text{CH}_3 - \text{C} = \text{CH} - \text{CH}_3 \\ \text{Geometrical isomers (cis-trans)} \\ \text{Molecule is optically active enantiomers} \\ \end{array}$ $\text{Geometrical isomer and enantiomers both are stereoisomers}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}