Import Question JSON

Current Question (ID: 21265)

Question:

$\text{The correct stability order of the resonating structure of the given compound is:}$ $\begin{array}{c} \text{O} \\ \text{||} \\ \text{H} - \text{C} = \text{C} - \text{C} = \text{C} - \text{NH}_2 \end{array}$

Options:

1. $\text{A} > \text{B} > \text{C}$
2. $\text{B} > \text{A} > \text{C}$
3. $\text{C} > \text{A} > \text{B}$
4. $\text{B} > \text{C} > \text{A}$

Solution:

$\text{Hint: a negative charge that is not on the most electronegative atom or a positive charge that is not on the least electronegative (most electropositive) atom}$ $\text{The features that decrease the predicted stability of a contributing resonance structure are as follows:}$ $1. \text{an atom with an incomplete octet}$ $2. \text{a negative charge that is not on the most electronegative atom or a positive charge that is not on the least electronegative (most electropositive) atom}$ $3. \text{charge separation}$ $\text{The positive charge on a more electropositive atom and the negative charge on an electronegative atom is more stable. Thus, structures (A) and (B) are more stable than structures (C) because of the positive charge on oxygen which is more electronegative.}$ $\text{Comparing (A) and (B), in (B) lone pair of electrons on -NH}_2 \text{ and a negative charge on carbon creates repulsion which makes less (B) stable than (A).}$ $\text{Thus, option one is the correct answer and order is A > B > C}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}